SOLUTION: 1/3(s-2)=s +4
I first distribute, and I got s/3-2/3=s +4
I added 2/3 and ended up with s/3= 14/3 is this right or am I missing a step?
Algebra.Com
Question 100895: 1/3(s-2)=s +4
I first distribute, and I got s/3-2/3=s +4
I added 2/3 and ended up with s/3= 14/3 is this right or am I missing a step?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
what happened to the s that was added to the 4?
multiplying the original equation by 3 gives s-2=3s+12
-2s=14 ... s=-7
RELATED QUESTIONS
Factor.
{{{s^2+6s+9}}}
i got 2 different answer can someone help?
i got... (answered by josmiceli)
I am reviewing for a test and I think I got the first 3 right. Can anybody check my... (answered by Alan3354)
I need to simplify this as much as possible:
(s+(1)/(4))*(s+(1)/(3))
In other words (answered by Maths68)
I need help please.
Deviding rational expressions.
s^2- 5s s-3
-------- /... (answered by Earlsdon)
Simplify by removing factors of 1.
s^2-9/(s+3)^2
I came up with s+9/s-3, but that is... (answered by richwmiller,scott8148)
I am trying to solve the following proportion problem:
"If p varies proportionally to... (answered by Boreal,ikleyn)
1/3(s-2)=s+4 (answered by AnlytcPhil)
1/3(s-2)=s+4
(answered by HyperBrain)
1/3(s-2)=... (answered by Fombitz)