SOLUTION: Factor the trinomial 36x^2 +5x-50 into the form (Ax+B)(Cx+D) with A, B, C, and D integers, and A and B non-negative. Find the value of A+B+C+D.

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Question 1003617: Factor the trinomial 36x^2 +5x-50 into the form (Ax+B)(Cx+D) with A, B, C, and D integers, and A and B non-negative. Find the value of A+B+C+D.
Found 3 solutions by stanbon, MathTherapy, mp2019:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Factor the trinomial 36x^2 +5x-50 into the form (Ax+B)(Cx+D) with A, B, C, and D integers, and A and B non-negative. Find the value of A+B+C+D.
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Use the AC Method to factor::
Note;
-45*40 = 36*-50 = -1800
45+40 = +5
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Rewrite the trinomial as::
36x^2 -45x+40x - 50
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Factor to get::
9x(4x-5)+10(4x-5)
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(4x-5)(9x+10)
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A + B + C + D = 4-5+9+10 = 18
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Cheers,
Stan H.
Answer by MathTherapy(10553)   (Show Source): You can put this solution on YOUR website!

Factor the trinomial 36x^2 +5x-50 into the form (Ax+B)(Cx+D) with A, B, C, and D integers, and A and B non-negative. Find the value of A+B+C+D.
Factor the trinomial to get: 

A = 4

B = 5

C = 9

D = - 10

A + B + C + D = 4 + 5 + 9 - 10, or  

Answer by mp2019(1)   (Show Source): You can put this solution on YOUR website!
 First, factor the equation:



(4x + 5)(9x - 10)

 A    B  C    D

------------

4+5+9-10=8 

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