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Tutors Answer Your Questions about absolute-value (FREE)
Question 204172: Solve each inequality. Graph each solution set.
The absolute value of x is greater than x-1.
I can see that the answer is all reals (by plugging in various numbers from either end of the number line), but how is the equation solved mathmatically?
Thank you,
Stella M. Hoy
P.S. This question comes from a worksheet. Glencoe/McGraw-Hill Student Edition Pages 49-54 Practice 1-7 T7 question #10 (Summer Work).
Click here to see answer by stanbon(26274)   |
Question 204633: Solve for real values of x.
absolutevalue(x-3) = 3-x
I know to set the absolute value up to equal a positive and negative possiblity and so that makes
x-3 = 3-x and x-3 = -3+x
For the first I got x = 3 but the second I got 0 = 0 and that's where I am confused. Did I do something wrong?
Click here to see answer by jim_thompson5910(13794) |
Question 204633: Solve for real values of x.
absolutevalue(x-3) = 3-x
I know to set the absolute value up to equal a positive and negative possiblity and so that makes
x-3 = 3-x and x-3 = -3+x
For the first I got x = 3 but the second I got 0 = 0 and that's where I am confused. Did I do something wrong?
Click here to see answer by Edwin McCravy(2922) |
Question 204745: what is the solution set for /-q/ = 7
I know that /q/ = 7 (7, -7)
But if q is negative, then I'm wondering if for some reason a negative would cancel out the negatvie in -q. Am I thinking too hard on this?
What is the answer and why?
Click here to see answer by Alan3354(6082)  |
Question 205336: Use the Theorem of Pythagoras a2 +b2 = c2 to calculate the following: (7)
A point on the ground is 6 m from a pole that is 12 m tall. Calculate the length of a straight line between this point and the top of the pole.
Click here to see answer by nerdybill(2446)  |
Question 207253: Can you please help me with these? I need more clarity on working this one out.
|10(-5)| + 1(-1)
( the two lines at the beginning of the equation: | 10 (-5)| are called the absolute value bars)
Whatever you can do will be greatly appreciated.
Click here to see answer by jim_thompson5910(13794) |
Question 209307: i going to use I for my absolute value signs!
MY promblem say: the absolute value of 2+3x is grater then or equal to - 13! we have gone over promblems like this before but not with a negative on the 13! please help me and explain to me how to solve this! i just don't understand!
Click here to see answer by stanbon(26274) |
Question 209593: Solve each equation. Check for extraneous solutions.
Equation: |5x-1|+7=3x
Here's what I did:
|5x-1|+7=3x
-7 -7
|5x+1|=3x-7
5x-1=3x-7 OR 5x-1=-(3x-7)
+1 +1
5x=3x-6
-3x -3x
2x=-6
-- --
2 2
x=-3
OR
5x-1=-(3x-7)
5x-1=-3x
So, x=-3 or x=1.
CHECK:
|5x-1|+7=3x
|5(-3)-1|+7=+3(-3)
|-15-1|+7=-9
|-16|+7=-9
16+7=-9
23=9
But 23 doesn't equal 9. At first I thought it was just an exraneous solution. But then I checked the second number:
|5x-1|+7=3x
|5(1)-1|+7=3(1)
|5-1|+7=3
|4|+7=3
4+7=3
11=3
But again, 11 doesn't equal 3.
Click here to see answer by stanbon(26274) |
Question 209930: PLEASE HELP ME!!! (:
1. FIND THE ABSOLUTE VALUE
[-1/2]
I cant write it in fraction form.I'm sorry :(
2. ORDER FROM LEAST TO GREATEST
-3 4/9, -3.45, -3 12/25
3. ORDER FROM LEAST TO GREATEST
2 3/4, 2 5/8, 2.7
DETERMINE WHICH SET OF NUMBERS IS MOST REASONABLE FOR EACH SITUATION.
4. The circumference of a compact disk.
Click here to see answer by nyc_function(260)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485
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