Instead of doing your problem for you, I'll do one EXACTLY IN EVERY DETAIL like yours. Then you can use it as a model to solve yours by. |x-2| - 7 ≤ 3 Add 7 to both sides |x-2| ≤ 10 ±(x-2) ≤ 10 Make two inequalities by using +(x-4) in one and -(x-4) in the other +(x-2) ≤ 10 -(x-2) ≤ 10 x-2 ≤ 10 -x+2 ≤ 10 x ≤ 12 -x ≤ 8 x ≥ -8 (reversing because we divided by a negative) x ≤ 12 says we shade left of 12 and x ≥ -8 says we shade right of -8. So we do both, darkening the endpoints because the inequalities are ≤ and ≥, rather than < and >. --------●===========================================================●------ -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 That says we put -8 on the left, then ≤ x to stand for all the shaded part of the number line and a ≤ 12 on the right Answer: -8 ≤ x ≤ 12 Now do yours EXACLY the same way. Edwin