SOLUTION: |8x+3|>0
I come up with (-3/8, ∞), but the book has (-∞,-3/8)U(-3/8, ∞).
Can someone walk me through and explain this?
Algebra.Com
Question 976841: |8x+3|>0
I come up with (-3/8, ∞), but the book has (-∞,-3/8)U(-3/8, ∞).
Can someone walk me through and explain this?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
|8x+3|>0
I come up with (-3/8, ∞), but the book has (-∞,-3/8)U(-3/8, ∞).
Can someone walk me through and explain this?
***
(8x+3) inside the absolute sign could be positive or negative and you must solve the equation for both possibilities.
..
assume (x+3)>0, just remove the absolute sign and solve the inequality.
8x+3>0
8x>-3
x=>-3/8
..
assume (8x+3)<0,affix a negative sign to (8x+3)( and solve the inequality.
-(8x+3)>0
-8x-3>0
-8x>3
divide by (-1) and reverse inequality sign
8x<-3
x<-3/8
number line:
<===)-3/8(====.>
(-∞, -3/8) U (-3/8, ∞)
note: domain does not include -3/8
RELATED QUESTIONS
I am stuck on this problem.
Solve the compound inequality 6>-4x+5 or 12≤-3x+5?... (answered by stanbon,Edwin McCravy)
Solve the absolute value inequality?
|8x-1|-7>-11
A.(-3\8,∞)
b.(-3/8,5/8)... (answered by Alan3354)
Give the domain
f(x)= x^4+4/x^2+6x-16
Answer shows (-∞,-8)u(-8,2)u(2,∞)
(answered by Theo,stanbon)
I am very confused with the end behavior of a Polynomial. Someone please help me with... (answered by richard1234)
Solve the compound inequality.
5 > - 2x + 4 or 8 < or = to -2x + 3
I came up with... (answered by John10)
What is each piece of information telling about the function exactly?
The function has (answered by jim_thompson5910)
Please tell me if my process is right or wrong.
lim x->-∞... (answered by Fombitz)
TABLE OF SIGNS
Suppose:
x + 10/(x − 17)^2 ≥ 0
Create a table of signs... (answered by Fombitz)
I am having a tough time solving this problem, any help would be much appreciated.... (answered by Fombitz)