SOLUTION: The length of a rectangle is 3 less than 5 times of its width. write a simplified algebraic expression for the perimeter of a rectangle. if the rectangle width is tripled and its

Question 957614: The length of a rectangle is 3 less than 5 times of its width.
write a simplified algebraic expression for the perimeter of a rectangle.
if the rectangle width is tripled and its length is doubled the perimeter of new rectangle is 92 cm greater than original perimeter.
Find the area of the original rectangle.
PLZZZ explain how u solved this?
and fast plz!!!!
Found 3 solutions by josgarithmetic, macston, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
Length, L, width w.
The length of a rectangle is 3 less than 5 times of its width.
.

p, perimeter of the rectangle.

if the rectangle width is tripled and its length is doubled the perimeter of new rectangle is 92 cm greater than original perimeter.

Now the dimensions are changed to width and length . The new perimeter is given as .

The question is, find the area of the original rectangle, but you need to solve for w, and then for L so that the area can be calculated. Return to the perimeter formula for using with the new perimeter situation.

, with the expressions substituted.

----------Use the given formula for L to find value of L.

Original rectangle's area, .
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
W=width; L=length=5W-3; P=perimeter
Original rectangle:
P=2(L+W) Substitute for L
P=2((5W-3)+W)=6W-3=12W-6
Original perimeter is 12W-6
New rectangle:
; =
=
New perimeter is 26W-12
New perimeter-original perimeter=92 cm

The original width was 7cm.
L=5W-3=5(7cm)-3=35cm-3cm=32cm The original length was 32cm.
Area=L*W=32cm*7cm=224 sq cm
ANSWER: The area of the original rectangle is 224 square centimeters.
CHECK
New Perimeter-Original Perimeter=92cm
2(2L+3W)-2(L+W)=92cm
2(64cm+21cm)-2(32cm+7cm)=92cm
2(85cm)+2(39cm)=92cm
170cm-78cm=92cm
92cm=92cm

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The length of a rectangle is 3 less than 5 times of its width.
write a simplified algebraic expression for the perimeter of a rectangle.
if the rectangle width is tripled and its length is doubled the perimeter of new rectangle is 92 cm greater than original perimeter.
Find the area of the original rectangle.
PLZZZ explain how u solved this?
and fast plz!!!!

Area of original rectangle:
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