SOLUTION: Is (R-{0},*) a group, how to prove it...
Algebra.Com
Question 935113: Is (R-{0},*) a group, how to prove it...
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
Consider, (R*,*) where R* = R - {0} IS a group.
multiplication in R is associative, so remains associative on any subset of R.
the product of two non-zero real numbers is again a non-zero real number, R* is closed under multiplication.
1 functions as a multiplicative identity:
for any NON-ZERO real number a, a*1 = 1*a = a.
any non-zero real number a has a (unique) inverse, 1/a, with
a*(1/a) = (1/a)*a = 1.
RELATED QUESTIONS
Use coordinate geometry to prove that triangle PQR is isosceles...
^
|
|---------Q... (answered by hovuquocan1997)
show that the binary operation is a group and determine if it is Abelian
H =... (answered by venugopalramana)
Given a geometric series with first term a > 0 and common ration r > 0 prove that a... (answered by richard1234)
define a binary * on R*=R without 0 by
a*b =ab if > 0 and a/b if a<0.
Determine whether (answered by richard1234)
Hi, I have no idea how to prove this. Any help appreciated. Thank you
Let f(x) = ax^3 + (answered by ikleyn,math_tutor2020)
For r≠1, use mathematical induction to prove that... (answered by lynnlo)
Prove that the set of all 3 x 3 matrices with real entries of the form
[ 1 a b
0 1 c
(answered by rahul)
From Abstract Algebra class.
Consider Z9 - { [ 0 ] } with respect to multiplication [... (answered by ikleyn)
how do i prove W^(perpendicular sign) is a subspace of... (answered by venugopalramana)