SOLUTION: Hello Tutors!
I'm preparing for NMAT. Can you please teach me how to solve problems like this: (3^n+2) ÷ (3^n+3 - 3^n+1)?
Note: This symbol (^) is the exponent of the three #
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Question 905303: Hello Tutors!
I'm preparing for NMAT. Can you please teach me how to solve problems like this: (3^n+2) ÷ (3^n+3 - 3^n+1)?
Note: This symbol (^) is the exponent of the three # 3s. The (^n+2) is the exponent of the first # 3; (^n+3) is the exponent of the second # 3; and the (^n+1) is the exponents of the third # 3.
I would really appreciate your help.
Thank you. :-)
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
i'll take a stab at it.
start with
factor out the greatest common factor from the denominator to get:
the factoring is correct because, by the laws of exponent arithmetic:
= =
and, by the same laws:
=
since is equal to , your expression becomes:
by the laws of exponent arithmetic:
= = = =
your expression becomes:
that's your solution.
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