SOLUTION: Hello Tutors! I'm preparing for NMAT. Can you please teach me how to solve problems like this: (3^n+2) ÷ (3^n+3 - 3^n+1)? Note: This symbol (^) is the exponent of the three #

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Question 905303: Hello Tutors!
I'm preparing for NMAT. Can you please teach me how to solve problems like this: (3^n+2) ÷ (3^n+3 - 3^n+1)?
Note: This symbol (^) is the exponent of the three # 3s. The (^n+2) is the exponent of the first # 3; (^n+3) is the exponent of the second # 3; and the (^n+1) is the exponents of the third # 3.
I would really appreciate your help.
Thank you. :-)

Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
i'll take a stab at it.

start with

factor out the greatest common factor from the denominator to get:



the factoring is correct because, by the laws of exponent arithmetic:

= =

and, by the same laws:

=

since is equal to , your expression becomes:



by the laws of exponent arithmetic:

= = = =

your expression becomes:



that's your solution.






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