SOLUTION: factor out completely
x^3-64
Algebra.Com
Question 836620: factor out completely
x^3-64
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
factor out completely
x^3-64
can be factored as the "difference of cubes": u^3 - v^3 = (u - v)(u^2 + uv + v^2)
so we have
x^3 - 64 = (x - 4)(x^2 + 4x + 16)
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