SOLUTION: factor out completely
8x^3+27
Algebra.Com
Question 836292: factor out completely
8x^3+27
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Use the sum of cubes rule to get...
8x^3+27
(2x)^3+3^3
(2x+3)((2x)^2-2x*3+(3)^2)
(2x+3)(4x^2-6x+9)
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