SOLUTION: What is the absolute value of 1-8i ?
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Question 809384
:
What is the absolute value of 1-8i ?
Found 2 solutions by
Edwin McCravy, edjones
:
Answer by
Edwin McCravy(20056)
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|a+bi| = √
a²+b²
|1-8i| = √
(1)²+(-8)²
= √
1+64
= √
65
Edwin
Answer by
edjones(8007)
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Show Source
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put this solution on YOUR website!
|a+bi|=sqrt(a^2+b^2)
|1-8i|
=sqrt(1^2+(-8)^2)
=sqrt(1+64)
=sqrt(65)
.
Ed
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