SOLUTION: 16:
8(c^3 - c) = c (6c + 1)
Algebra.Com
Question 80724: 16:
8(c^3 - c) = c (6c + 1)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
8(c^3 - c) = c (6c + 1)
8c^3-8c = 6c^2+c
8c^3-6c^2-8c-c=0
c(8c^2-6c-9)=0
c(4c+3)(2x-3)0
c=0 or c=-3/4 or c=3/2
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Cheers,
Stan H.
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