We get it in the form

y = a|x-h|+k  has vertex (h,k), which is the point at the V.

So we get

y = 3|x-3| + 6 in the form y = a|x-h| + k

y = 3|x-3| + 6

Factor out  inside the absolute value

y = 3|(x-6)| + 6

y = 3·|x-6| + 6

y = |x-6| + 6

Compare that to

y = a|x-h| + k  which has vertex (h,k)

a = , h=6, k=6, so the vertex is (6,6)

We get two points, one on each side of the vertex (6,6)

and draw the V-shaped graph

The graph is:



Edwin