SOLUTION: Having trouble with this concept.Category is "replacement sets" the question posed is- b-(-3b-3)=4b+3.the correct set is 2.....but then the confusion with me is-again-2-(-6-3) whic
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Question 789983: Having trouble with this concept.Category is "replacement sets" the question posed is- b-(-3b-3)=4b+3.the correct set is 2.....but then the confusion with me is-again-2-(-6-3) which is-2-(-9)=11? the other side of equation is ok(11 of course).Is it because the 2 negative signs(one inside parenthesis)and the positive 2 in front makes the 9 positive???? One final question-any number inside absolute value sign will become positive-if the number is negative....but positive number cannot become negative?
Found 2 solutions by solver91311, MathLover1:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
No.
\ \not =\ 11)
\ =\ -2\ +\ 9\ =\ 7)
But 
,
So what is the problem here? Either 2 is NOT the correct replacement set, or that minus sign you have in front of the 2 in the LHS of your equation is spurious.
If the problem is
\ =\ 4b\ +\ 3)
Then
And that is true no matter what value you substitute for 
, so 2 would work just fine as in:
\ -\ 3)\ =\ 4(2)\ +\ 3)
But it would work just as well if 
\ -\ 3)\ =\ 4(125)\ +\ 3)
But if the problem is
\ =\ 4b\ +\ 3)
Then
Which is only true if 
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
...we can prove that left side is equal to right side
...proof
as you said, the other side of equation is ok(11 of course).Is it because the 2 negative signs(one inside parenthesis)and the positive 2 in front makes the 9 positive--this is
now, your question: any number inside absolute value sign will become positive-if the number is negative
that is ; recall definition of absolute value
the absolute value of a number is the the number is (on a number line}}}
example:
, on number line is units to the left from zero
, on number line is units to the right from zero
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