SOLUTION: Can someone solve this a simple way?
1.)-5|x-5|-15 < 0
2.)-4+2|x-37|=20
Algebra.Com
Question 731914: Can someone solve this a simple way?
1.)-5|x-5|-15 < 0
2.)-4+2|x-37|=20
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1.)-5|x-5|-15 < 0
----
-5|x-5| < 15
|x-5| > -3
----
Since |x-5| is never negative, you
have |x-5| >= 0
---
x-5 >= 0 or x-5 <= 0
---
x >= 5 or x <= 5
----
Conclusion: x is all possible Real Number values.
===========================
2.)-4+2|x-37|=20
---
2|x-37| = 24
|x-37| = 12
x-37 = 12 or x-37 = -12
x = 49 or x = 25
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Cheers,
Stan H.
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