SOLUTION: How do you determine if an absolute value inequality's solution is all real numbers? Example: |2x-5| is greater than-3 and |2x-5| is less than -3

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Question 710771: How do you determine if an absolute value inequality's solution is all real numbers? Example: |2x-5| is greater than-3 and |2x-5| is less than -3
Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
|2x-5| is greater than-3 and |2x-5| is less than -3
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Note: Absolute value expressions cannot be negative.
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If |2x-5| > -3 it must be >= 0
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|2x-5| >= 0 for all Real Numbers
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Cheers,
Stan H.

Answer by Edwin McCravy(20064)   (Show Source): You can put this solution on YOUR website!
The other tutor apparently thought the second one was 
greater, but it was less

|2x-5| < -3

Absolute values are always either positive or 0.
So it would be impossible for |2x-5| to be less than
-3, for to do so, it would have to be negative, and 
it is impossible for an absolute value to be negative.

So that one would have no solutions.

Edwin
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