SOLUTION: Lucy has a pile of 50 dimes and nickels worth $4.30. How many of each coin does she have?

SOLUTION: Lucy has a pile of 50 dimes and nickels worth $4.30. How many of each coin does she have?

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Question 70588This question is from textbook Algebra:Structure and Method
: Lucy has a pile of 50 dimes and nickels worth $4.30. How many of each coin does she have? This question is from textbook Algebra:Structure and Method

Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
N+D=50
N=50-D
5N+10D=430
5(50-D)+10D=430
250-5D+10D=430
5D=430-250
5D=180
D=180/5
D=36 NUMBER OF DIMES.
N+36=50
N=50-36
N=14 NUMBER OF NICKLES.
PROOF
5*14+10*36=430
70+360=430
430=430
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