SOLUTION: Find the absolute extreme values of f(x)=3x^5-15x^4-25x^3 on the interval [-2,3] please help!

Question 676223: Find the absolute extreme values of f(x)=3x^5-15x^4-25x^3 on the interval [-2,3]
please help!
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
Take the derivative to get 15x^4 - 60x^3 - 75x^2
Factor out a 15x^2 to get x^2-4x-5 This factors into 15x^2(x-5)(x+1).
Then you would get 0,-1,5 are your critical points. But 0 and -1 are the only things on your interval.
Then you plug in the end points:
f(-2) = -136
f(3) = -1161
And then plug in your critical values:
f(-1) = 7
f(0) = 0
Then 7 is your absolute maximum and -1161 is your minimum.
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