SOLUTION: I am working on an absolute value inequality for my algebra class. The problem is 9[1-z] is less than or equal to -36. For this questions [] represent absolute value.
To solve
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Question 651624: I am working on an absolute value inequality for my algebra class. The problem is 9[1-z] is less than or equal to -36. For this questions [] represent absolute value.
To solve this I used two cases of absolute value.
The first case is -(1-z)=<-4. I added one to each side of the equation to come up with z=<-3.
The second case is (1-z)=<-4. I added 1 to each side to get -z=<-5. Then I divided by -1. After dividing and flipping the sign I came up with z=>5.
The answer needs to be in set notation so the answer I came up with was [-3,5].
When I submitted my answer it was marked incorrect and I am not sure why. I honestly thought I was doing this correctly and I do not know where I messed up.
*For this question =< and => represent less than or equal to and greater than or equal to.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
the original equation is:
9*|1-x| <= -36
divide both sides of this equation by 9 to get:
|1-x| <= -36/9 which simplifies to:
|1-x| <= -4
this leads to 2 equations:
(1-x) <= -4
-(1-x) <= -4
so far so good.
-----
solving for (1-x) <= -4:
remove parentheses to get:
1-x <= -4
subtract 1 from both sides of the equation to get:
-x <= -5
multiply both sides of the equation by -1 to get:
x >= 5
-----
solving for -(1-x) <= -4:
remove parentheses to get:
-1+x <= -4
add 1 to both sides of the equation to get:
x <= -3
-----
your 2 solutions are:
x >= 5 or x <= -3
-----
this appears to agree with what you derived.
placing it in interval notation would indicate the following:
(-infinity,-3] union [5,+infinity)
i believe this is where you went wrong.
x <= -3 means that x goes from minus infinity up to and including -3.
that's where the interval notation of (-infinity,-3] comes in.
note that this is interval notation and not set notation.
x >= 5 means that x goes from 5 to plus infinity. since 5 is included in the solution set, the interval becomes:
[5,+infinity)
the (-infinity means that the value is greater than minus infinity.
the +infinity) means that the value is less than plus infinity.
the -3] means that the value is less than or equal to -3.
the [5 means that the value is greater than or equal to 5.
not again that this is interval notation, not set noation.
in set notation, the answer would be shown as:
{x | x <= -3 or x >= 5}
or:
{x element of real numbers | x <= -3 or x >= 5}
i'd say you got the answer correct but displayed it wrong.
here's a reference on interval notation and set notation.
http://www.regentsprep.org/Regents/math/ALGEBRA/AP1/IntervalNot.htm
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