To draw the graph of the form: y = a·|bx + c| + d This is a graph shaped like this "⋁" or like this "⋀". 1. Find the vertex (The sharp point of the graph) A. Set bx + c = 0 and solve for x. This is the x-coordinate of the vertex. B. The y-coordinate of the vertex is d. C. Plot this point. 2. Find a point on the left of the vertex A. Select a value of x less than the x coordinate of the vertex for the x-ccordinate of a second point on the graph. B. Substitute this value into the equation to find the corresponding y-coordinate for that point. C. Plot that point. 3. Find a point on the right of the vertex A. Select a value of x greater than the x coordinate of the vertex for the x-ccordinate of a third point on the graph. B. Substitute this value into the equation to find the corresponding y-coordinate for that point. C. Plot that point. 4. Draw a graph through those three points shaped like this "⋁" or like this "⋀", with the vertex at the sharp point. ----------------- Let's go through your problem with those rules. y = |3x - 6| + 1 Compare to y = a·|bx + c| + d a=1, b=3, c=-6, d=1 1. Find the vertex (The sharp point of the graph) A. Set bx + c = 0 and solve for x. 3x - 6 = 0 3x = 6 x = 2 This is the x-coordinate of the vertex. B. The y-coordinate of the vertex is d=1. C. Plot this point, which is (2,1)2. Find a point on the left of the vertex A. Select a value of x less than the x coordinate of the vertex for the x-ccordinate of a second point on the graph. Let's select 1 which is less than 2 B. Substitute this value into the equation to find the corresponding y-coordinate for that point. y = |3x - 6| + 1 y = |3(1) - 6| + 1 y = |3 - 6| + 1 y = |-3| + 1 y = 3 + 1 y = 4, so the second point is (1,4) C. Plot that point. 3. Find a point on the right of the vertex A. Select a value of x greater than the x coordinate of the vertex for the x-ccordinate of a third point on the graph. Let's select 3 which is greater than 2 B. Substitute this value into the equation to find the corresponding y-coordinate for that point. y = |3x - 6| + 1 y = |3(3) - 6| + 1 y = |9 - 6| + 1 y = |3| + 1 y = 3 + 1 y = 4, so the third point is (3,4) C. Plot that point. 4. Draw a graph through those three points shaped like this "⋁" or like this "⋀", with the vertex at the sharp point. In this case it is shaped like this "⋁", so we draw in the graph: Edwin