SOLUTION: [2x+3]> 17
with > being greater than or equal to. Please help me I have midterm exam coming up!
Algebra.Com
Question 544114: [2x+3]> 17
with > being greater than or equal to. Please help me I have midterm exam coming up!
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
[2x+3]≥ 17
solve for two conditions:
for (2x+3)>0
2x+3≥ 17
2x≥14
x≥7
..
for (2x+3)<0
-2x-3≥ 17
-2x≥20
divide by -2 and reverse inequality sign
x≤-10
..
number line:
<===-10].......[7===>
solution:
(-∞,-10] U [7,∞)
RELATED QUESTIONS
I am supposed to come up with a quadratic inequality that solution set is satisfied with... (answered by ankor@dixie-net.com)
Can I please have help with this, thank you!
Graph the following systems of... (answered by Alan3354,ikleyn)
Can someone please help me come up with the proper inequality equation? Thanks!... (answered by mathslover)
Hi,
I am having trouble in knowing which side i am supposed to shade, i know that if it... (answered by MathLover1)
I'm doing solving and graphing inequalities y>2x+3
I have solved a different problem... (answered by AdolphousC)
My exam review has a section on functions that says Evaluate [-77.99], [3.5] and |-7| +... (answered by richard1234)
how do you solve -5x-(2x+3) is greater than or equal to 1? I have tried practically... (answered by algebrahouse.com)
Please help me graph the inequality?
2x + 5y is greater than or equal to... (answered by stanbon)
Can I please have help with this, Thank you!
On the grid, sketch the inequalities... (answered by math_tutor2020)