# SOLUTION: SOMEONE PLEASE HELP ME WITH THIS PROBLEM: IF f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x)>0.

Algebra ->  Algebra  -> Absolute-value -> SOLUTION: SOMEONE PLEASE HELP ME WITH THIS PROBLEM: IF f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x)>0.       Log On

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 Algebra: Absolute value Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on absolute-value Question 54409This question is from textbook ALGEBRA AND TRIGONOMETRY : SOMEONE PLEASE HELP ME WITH THIS PROBLEM: IF f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x)>0. This question is from textbook ALGEBRA AND TRIGONOMETRY Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!f(x) must be greater than the value of zero 0 < x(x + 3)(x - 1) The zeros for x(x + 3)(x - 1) is at x=0, x=-3, and x=1. Pick Points: <```(-3)```(0)```(1)```> x = -4 0 < (-4)(-4 + 3)(-4 - 1) 0 < (-4)(-1)(-5) 0 < -20 Not True <---(-3)```(0)```(1)```> x = -1 0 < (-1)(-1 + 3)(-1 - 1) 0 < (-1)(2)(-2) 0 < 4 True <---(-3)====(0)```(1)```> x = 0.5 0 < (0.5)(0.5 + 3)(0.5 - 1) We already know we will get a negative number, so this is false. <---(-3)====(0)----(1)```> x = 2 0 < (2)(2 + 3)(2 - 1) 0 < (2)(5)(1) 0 < 10 This is true. <---(-3)====(0)----(1)====> (-3,0)U(1,+)