# SOLUTION: [11+2x]=5, [8x+1]=23, [1/2x-3]=2 how do i solve these equations?

Algebra ->  Algebra  -> Absolute-value -> SOLUTION: [11+2x]=5, [8x+1]=23, [1/2x-3]=2 how do i solve these equations?       Log On

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 Algebra: Absolute value Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on absolute-value Question 50955This question is from textbook : [11+2x]=5, [8x+1]=23, [1/2x-3]=2 how do i solve these equations? This question is from textbook Answer by stanbon(57387)   (Show Source): You can put this solution on YOUR website!If you had |x|=3 you would know that x=3 or x=-3 ---------------- Similarly if[11+2x]=5 then 11+2x must be 5 or it must be -5, so: if 11+2x=5 then 2x=-6 and x=-3 --- if 11+2x=-5 then 2x=-16 and x=-8 -------- SOLUTION: x=-3 or -8 -------------------------------- The following problems follow the same pattern. [8x+1]=23, [1/2x-3]=2 Cheers, Stan H.