SOLUTION: 2 LN 2 - ((LN 36) / 2) + (2/3 LN 27). I think it is: LN [(27 ^ (2/3))(2^2) / (36^.5) Is this how I rewrite it.

Question 488756: 2 LN 2 - ((LN 36) / 2) + (2/3 LN 27). I think it is: LN [(27 ^ (2/3))(2^2) / (36^.5) Is this how I rewrite it.
Found 2 solutions by stanbon, 12cleo:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2 LN 2 - ((LN 36) / 2) + (2/3 LN 27).
I think it is: LN [(27 ^ (2/3))(2^2) / (36^.5) Is this how I rewrite it.
=========================================================
2 LN(2) - ((LN(36) / 2) + (2/3) LN 27
-------------------
= ln(4) - ln(36^(1/2)) + ln(27^(2/3))
-------------------
= ln(4) - ln(6) + ln(9)
------
= ln[4*9/6]
------
= ln(6)
=================
Cheers,
Stan H.
Answer by 12cleo(1) (Show Source): You can put this solution on YOUR website!
LN(6)
RELATED QUESTIONS
Rewrite the expression 3 ln(2) - 2 ( ln(10) - ln(4) ) in the form ln(x), a single... (answered by stanbon,josmiceli)
Solve: log base 4 (X) + Log base 8 (x) = 1 ln X/ln 4 + ln X/ln 8=1 2 ln X/2 ln 4 + ln... (answered by Fombitz)
"Rewrite the expression 3 ln(4) - 2 ( ln(10) - ln(2) ) in the form ln(x), a single... (answered by jim_thompson5910)
Ln 3-2 ln 5+ ln... (answered by oscargut)
x= ln 3 + ln 4 - ln... (answered by jim_thompson5910)
ln 3 - 2(ln 4 + ln... (answered by tommyt3rd)
log6 (3) + log5 (2) is equivalent to A 0 B ln(2) * ln (6) C 1 / ln(6) D ln(2) / ln (answered by rapaljer)
I was just trying to establish if concluding the problem being: Re-write the following... (answered by lwsshak3)
Hello, I have a problem with the following exponential equation, each time I try to... (answered by RAY100)