SOLUTION: 1) solve: abs(2y+4)=22-abs(6-2y) 2) solve: abs(x-1)-abs(x+2)<abs(x+1)

Question 457034: 1) solve: abs(2y+4)=22-abs(6-2y)

2) solve: abs(x-1)-abs(x+2)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
1) solve: abs(2y+4)=22-abs(6-2y)
2) solve: abs(x-1)-abs(x+2)
**
1)abs(2y+4)=22-abs(6-2y)
|2y+4|=22-|6-2y|
let (2y+4)<0
-2y-4=22-6+2y
-4y=22-6+4=20
y=-5
..
|6-2y|=22-|2y+4|
let (6-2y)<0
-6+2y=22-2y-4
4y=22-4+6=24
y=6
..
2) solve: abs(x-1)-abs(x+2
y=|x-1|-|x+2|
for x<-2
y=-x+1-(-x-2)
y=-x+1+x+2=3
..
or x>1
y=x-1-x-2
y=-3
..
for -2 ≤ x ≤1
y=-x+1-(x+2)
y=-x+1-x-2
y=-2x-1
RELATED QUESTIONS
abs(x+1)/abs(x-1)>=2 (answered by josgarithmetic)

solve: (abs(x-1))^(x^2+3x)=(abs(x-1))^(5-x). Abs means Absolute (answered by ikleyn)

Abs... (answered by pv=nrt15rcks)

Solve... (answered by jim_thompson5910)

9. Solve... (answered by jim_thompson5910)

How can i solve these type of equations?? {{{ abs (x-4) - abs (x+2) =6}}} would the (answered by rothauserc)

Prove: abs(xy)=... (answered by robertb)

can you please help me solve these?? thanks! 1) abs(x/5)=2 2) 14+2... (answered by Jk22,jessica43)

{{{abs(3x + 1) + abs(3 - 2x) = 11}}} {{{x =... (answered by Fombitz,richwmiller,Edwin McCravy)