SOLUTION: solve the following system by substitution.
8x -4y=16
y=2x- 4
Algebra.Com
Question 45164: solve the following system by substitution.
8x -4y=16
y=2x- 4
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
8x -4y=16...................I
y=2x- 4......2X-Y=4...........II
EQN.I-EQN.II*4
8X-4Y-8X+4Y=16-16
0=0
HENCE THE EQNS.ARE DEPENDENT AND CONSISTENT.HENCE IT WILL HAVE INFINITE SETS OF SOLUTIONS..TAKE ANY EQN. SAY...EQN.II
Y=2X-4...GIVE ANY VALUE TO X..SAY..0..THEN Y=2*0-4=-4
SO (0,-4) IS A SOLUTION..LIKE WISE (1,-2),(2,0)ETC..IN GENERAL {X,2X-4}IS A SOLUTION.
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