SOLUTION: {{{1/2+((2x-1)/3)<=1}}} please help me sole this inequality in interval notation thank you note the ( ) are actually absolute value brackets

Question 439096:
please help me sole this inequality in interval notation
thank you
note the ( ) are actually absolute value brackets
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
1/2+|2x-1/3)|<=1
1/2+|2x-1|/3<=1 (pull out denominator 3)
LCD=6
3+2|2x-1|<=6
solve for two possibilities: (2x-1)>=0 or (2x-1)<0
..
3+2(2x-1)<=6
3+4x-2<=6
4x>=5
x>=5/4
..
3+2(-2x+1)<=6
3-4x+2<=6
-4x>=1 (divide by (-4) and reverse inequality sign
x<=-1/4
..
Solution:
(-infinity,-1/4] U [5/4,infinity)
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