# SOLUTION: Does |n + m| = |n| + |m| for all integers n and m? If so, give some examples. If not, give a counterexample. I would say no, because |6 + (-5)| = |6| + |-5| |1| = |6| + |-

Algebra ->  Algebra  -> Absolute-value -> SOLUTION: Does |n + m| = |n| + |m| for all integers n and m? If so, give some examples. If not, give a counterexample. I would say no, because |6 + (-5)| = |6| + |-5| |1| = |6| + |-      Log On

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 Click here to see ALL problems on absolute-value Question 352218: Does |n + m| = |n| + |m| for all integers n and m? If so, give some examples. If not, give a counterexample. I would say no, because |6 + (-5)| = |6| + |-5| |1| = |6| + |-5| 1 = 6 + 5 1 = 11 Not sure what to write for a counter example Found 2 solutions by jim_thompson5910, Fombitz:Answer by jim_thompson5910(28598)   (Show Source): You can put this solution on YOUR website!You are correct. in general and you just gave a counterexample. Answer by Fombitz(13828)   (Show Source): You can put this solution on YOUR website!What you wrote is a counterexample. You showed one case where does not hold. You only need to show it for one example, which you did.