SOLUTION: Graph this absolute value. Y=|2x-5| I used -3,-2,-1,0,1,2,3 as x but i cannot get a "V" shape graph. I know the v has to be on the x axis and i think that y=0 at least once but

Question 348364: Graph this absolute value. Y=|2x-5|
I used -3,-2,-1,0,1,2,3 as x but i cannot get a "V" shape graph. I know the v has to be on the x axis and i think that y=0 at least once but there is no value that will make y=0. Im not sure, but does this problem have a soultion?
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The vertex of the V occurs when the argument equals zero.

Then using this x poisitoin as an axis of symmetry, you can calculate values that have same y value.
1.5,3.5
0,5
etc.

RELATED QUESTIONS
I need help. I'm supposed to solve and graph this equation y=absolute value of x-4 but... (answered by stanbon)

I need to graph this absolute value function: t(x) = 3- the absolute value x.(I don't... (answered by stanbon)

Help! Please! I already submitted these, but didn't get any answers. Thanks! 2/v -... (answered by Alan3354)

y= (x+4)-(x+1) the (brackets) are supposed to be the absolute value bar lines i... (answered by stanbon)

Here is my problem, concerning vectors and norms(?) I have the following information: u (answered by jim_thompson5910)

I am trying to work on the following proof. I know I used DEM incorrectly on line 3. I... (answered by jim_thompson5910)

how would you graph the quadratic equation {{{y<-x^2+2x+1}}} and graph it as a parabala?... (answered by stanbon)

#3 what does this look like in a graph after being plotted out? First, set Y to 0 then... (answered by Alan3354)

evertime i try to graph my absolute equation i don't get a v-shape graph my dots are... (answered by stanbon)