SOLUTION: This seems like it would be so obvious but it's giving me a hard time... Can you help me with adding {{{abs(3pi -7)}}} and {{{abs(7pi -26)}}} I don't see how it can't be {{{1

Algebra ->  Absolute-value -> SOLUTION: This seems like it would be so obvious but it's giving me a hard time... Can you help me with adding {{{abs(3pi -7)}}} and {{{abs(7pi -26)}}} I don't see how it can't be {{{1      Log On


   



Question 336577: This seems like it would be so obvious but it's giving me a hard time...
Can you help me with adding abs%283pi+-7%29 and abs%287pi+-26%29
I don't see how it can't be 10pi%2B33
Please help.
Thanks in advance.

Found 3 solutions by Alan3354, Theo, Edwin McCravy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Can you help me with adding the absolute value of 3pie -7 and the abs 7pie -26
I don't see how it can't be 10pie+33
---------------
If you mean pi, then there's no variable, all constants, just numbers.
-----------------
3pi - 7 =~ +2.4248
10pi - 33 =~ -1.584 --> |10pi - 33| = 33 - 10pi
------------
Adding them --> 26 - 7pi
=~ 4.0088
--------------

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
Assume it's true and see what happens.

You would get:

abs(3*pi-7) + abs(7*pi-26) = 10*pi + 33.

Since pi is equal to 3.141592654 (roughly), then this would translate to:

abs(2.424777961) + abs(-4.008851425) = 6.433629386.

since 10*pi + 33 =64.41592654 this is clearly not a true statement.

The only way this could be a true statement is if:

3*pi + abs(-7) + 7*pi + abs(-26) = 10*pi + 33


Answer by Edwin McCravy(20086) About Me  (Show Source):
You can put this solution on YOUR website!
abs%283pi+-7%29%22%22%2B%22%22abs%287pi+-26%29

To remove absolute value bars, you

1. Decide whether what is between the absolute value bars is a positive
number or a negative number.
2. If it is a positive number, simply replace the absolute value bars by
parentheses.
3. If it is a negative number, replace the absolute value bars by  
parentheses BUT PUT A - SIGN IN FRONT.

Between the absolute value bars of abs%283pi+-7%29, we have
3pi+-7.  We know that pi is approximately 3.14, so we
substitute 3.14 for pi and see whether that is a positive number 
or a negative number:

3%283.14%29+-7=9.42-7=2.42.  That is a positive number.  Now we don't
want to use 2.42 because that is only approximate.  We just did that
to find out whether 3pi+-7 is positive or negative.  We found out
that it is positive. So step 2 applies:

We just replace the absolute value bars by parentheses and so far we have:

%283pi+-7%29%22%22%2B%22%22abs%287pi+-26%29

Between the absolute value bars of abs%287pi+-26%29, we have
7pi-26.  We know that pi is approximately 3.14, so we
substitute 3.14 for pi and see whether that is a positive number 
or a negative number:

7%283.14%29-26=21.98-26=-4.02.  That is a negative number.  Now we don't
want to use -4.02 because that is only approximate.  We just did that
to find out whether 7pi+-26 is positive or negative.  We found out
that it is negative. So step 3 applies:

We replace the absolute value bars by parentheses BUT WE PUT A - SIGN IN 
FRONT.

%283pi+-7%29%22%22%2B%22%22-%287pi+-26%29

To keep two signs from coming together, we put brackets around the
second - sign and the parentheses:

%283pi+-7%29%22%22%2B%22%22%22%5B%22-%287pi+-26%29%22%5D%22

Now we remove the parentheses inside the brackets:

%283pi+-7%29%22%22%2B%22%22%22%5B%22-7pi+%2B26%22%5D%22

Now we remove the parentheses and the bracket:

3pi+-7-7pi+%2B26

Collect like terms:

-4pi%2B19

or so it won't begin with a -, make it

19-4pi

Edwin