SOLUTION: This seems like it would be so obvious but it's giving me a hard time...
Can you help me with adding {{{abs(3pi -7)}}} and {{{abs(7pi -26)}}}
I don't see how it can't be {{{1
Algebra ->
Absolute-value
-> SOLUTION: This seems like it would be so obvious but it's giving me a hard time...
Can you help me with adding {{{abs(3pi -7)}}} and {{{abs(7pi -26)}}}
I don't see how it can't be {{{1
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Question 336577: This seems like it would be so obvious but it's giving me a hard time...
Can you help me with adding and
I don't see how it can't be
Please help.
Thanks in advance. Found 3 solutions by Alan3354, Theo, Edwin McCravy:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Can you help me with adding the absolute value of 3pie -7 and the abs 7pie -26
I don't see how it can't be 10pie+33
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If you mean pi, then there's no variable, all constants, just numbers.
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3pi - 7 =~ +2.4248
10pi - 33 =~ -1.584 --> |10pi - 33| = 33 - 10pi
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Adding them --> 26 - 7pi
=~ 4.0088
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To remove absolute value bars, you
1. Decide whether what is between the absolute value bars is a positive
number or a negative number.
2. If it is a positive number, simply replace the absolute value bars by
parentheses.
3. If it is a negative number, replace the absolute value bars by
parentheses BUT PUT A - SIGN IN FRONT.
Between the absolute value bars of , we have
. We know that is approximately 3.14, so we
substitute 3.14 for and see whether that is a positive number
or a negative number:
. That is a positive number. Now we don't
want to use 2.42 because that is only approximate. We just did that
to find out whether is positive or negative. We found out
that it is positive. So step 2 applies:
We just replace the absolute value bars by parentheses and so far we have:
Between the absolute value bars of , we have
. We know that is approximately 3.14, so we
substitute 3.14 for and see whether that is a positive number
or a negative number:
. That is a negative number. Now we don't
want to use -4.02 because that is only approximate. We just did that
to find out whether is positive or negative. We found out
that it is negative. So step 3 applies:
We replace the absolute value bars by parentheses BUT WE PUT A - SIGN IN
FRONT.
To keep two signs from coming together, we put brackets around the
second - sign and the parentheses:
Now we remove the parentheses inside the brackets:
Now we remove the parentheses and the bracket:
Collect like terms:
or so it won't begin with a -, make it
Edwin