SOLUTION: A car radiator has a 6-liter capacity. If the liquid in the radiators 40% antifreeze, how much liquid must be replaced with pure anitfreeze to bring the mixture up to a 50% solutio

Question 319670: A car radiator has a 6-liter capacity. If the liquid in the radiators 40% antifreeze, how much liquid must be replaced with pure anitfreeze to bring the mixture up to a 50% solutions? If I told you the answer is 1 liter, in your own words, using complete sentences explain how you would solve this problem

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A car radiator has a 6-liter capacity. If the liquid in the radiators 40% antifreeze, how much liquid must be replaced with pure anitfreeze to bring the mixture up to a 50% solutions? If I told you the answer is 1 liter,
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Equation:
acid -acid + acid = acid
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0.40*6 - 0.40x + 1.00x = 0.50(6)
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Multiply thru 100 to get:
40*6 - 40x + 100x = 50*6
60x = 10*6
x = (1/6)*6
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x = 1 liter (amt. of 40% removed and replaced with 100% antifreeze)
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Cheers,
Stan H.
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