SOLUTION: please help me solve this equation :) abs(x+3) = abs(2x+1)

Question 263439: please help me solve this equation :)
abs(x+3) = abs(2x+1)
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
Here is the original question

---
this will be a bit tricky in that that we have 3 equations to solve.
equation #1:
x+3 = 2x+1
step 1 - subtract x and subtract 1 to get
2 = x
-----
equation #2:
x+3 = -(2x+1)
step 1 - distribute the - through to get
x+3 = -2x -1
step 2 - add 2x and subtract 3 to get
3x = -4
step 3 - divide to get
x = -4/3
-----
equation #3:
2x+1 = -(x+3)
step 1 - distribute the - through to get
2x + 1 = -x -3
step 2 - add x and subtract 1 to get
3x = -4
step 3 - divide to get
x = -4/3
----
so it appears that our answers are
x = -4/3, 2
-----
here are the graphs

RELATED QUESTIONS
Please help me to answer this question. Solve {{{(x)abs(5x-1) =... (answered by Fombitz)

Please help me solve this problem: (abs(x)/abs(x+2)) < 2 (answered by josgarithmetic)

Please Help me solve this equation: {{{sqrt(1-cosx)/sqrt(1+cosx)= (1- cosx)/... (answered by Alan3354)

Please help me solve this equation: {{{ 4 > abs(S^2+3)... (answered by stanbon)

can you help me solve this absolute value equation?... (answered by josmiceli)

can you please help me solve these?? thanks! 1) abs(x/5)=2 2) 14+2... (answered by Jk22,jessica43)

{{{abs(3x + 1) + abs(3 - 2x) = 11}}} {{{x =... (answered by Fombitz,richwmiller,Edwin McCravy)

This is giving me troubles please help me. Solve {{{abs((2x-1)/5)}}} >... (answered by Edwin McCravy)

Please show work. {{{ abs(2x - 3) = -1 }}} (answered by josgarithmetic)