SOLUTION: y = |2x - 6| - 2 what is the vertex of this problem when graphed and does the graph open upwards or downwards?

Algebra ->  Algebra  -> Absolute-value -> SOLUTION: y = |2x - 6| - 2 what is the vertex of this problem when graphed and does the graph open upwards or downwards?      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   


Question 214873: y = |2x - 6| - 2 what is the vertex of this problem when graphed and does the graph open upwards or downwards?
Answer by Edwin McCravy(6936) About Me  (Show Source):
You can put this solution on YOUR website!
+y+=+abs%282x+-+6%29+-+2

To find the vertex:
Set the expression between the absolute value bars
equal to zero, that's just the red part below:

+y+=+abs%28red%282x+-+6%29%29+-+2

red%282x-6%29=0
2x=6
x=3

Now find the y-value that corresponds to that
value of x:

+y+=+abs%282%283%29+-+6%29+-+2
+y+=+abs%286+-+6%29+-+2
+y+=+abs%280%29+-+2
+y+=+0+-+2
+y+=+-2

So the vertex is the point %27%283%2C-2%29%27}

So we plot that point:

drawing%28200%2C200%2C-5%2C7%2C-6%2C6%2C+%0D%0Agraph%28200%2C200%2C-5%2C7%2C-6%2C6%29%0D%0Aline%283%2B.1%2C-2%2C3-.1%2C-2%29%2C+line%283%2C-2%2B.1%2C3%2C-2-.1%29%2C+line%283%2B.1%2C-2%2B.1%2C3-.1%2C-2-.1%29%2C+line%283%2B.1%2C-2-.1%2C3-.1%2C-2%2B.1%29++%29 

Now find and plot one point on each side of that point:

So choose x to be 1 less than 3, which is 2, Substitute
in:

+y+=+abs%282x+-+6%29+-+2
+y+=+abs%282%282%29+-+6%29+-+2
+y+=+abs%284+-+6%29+-+2
+y+=+abs%28-2%29+-+2
+y+=+2+-+2
+y+=+0

So we plot the point %27%282%2C0%29%27

drawing%28200%2C200%2C-5%2C7%2C-6%2C6%2C+%0D%0Agraph%28200%2C200%2C-5%2C7%2C-6%2C6%29%2C%0D%0Aline%282%2B.1%2C0%2C2-.1%2C0%29%2C+line%282%2C0%2B.1%2C2%2C0-.1%29%2C+line%282%2B.1%2C0%2B.1%2C2-.1%2C0-.1%29%2C+line%282%2B.1%2C0-.1%2C2-.1%2C0%2B.1%29%2C%0D%0A%0D%0Aline%283%2B.1%2C-2%2C3-.1%2C-2%29%2C+line%283%2C-2%2B.1%2C3%2C-2-.1%29%2C+line%283%2B.1%2C-2%2B.1%2C3-.1%2C-2-.1%29%2C+line%283%2B.1%2C-2-.1%2C3-.1%2C-2%2B.1%29++%29 

Next choose x to be 1 more than 3, which is 4, Substitute
in:

+y+=+abs%282x+-+6%29+-+2
+y+=+abs%282%284%29+-+6%29+-+2
+y+=+abs%288+-+6%29+-+2
+y+=+abs%282%29+-+2
+y+=+2+-+2
+y+=+0

So we plot the point %27%284%2C0%29%27

drawing%28200%2C200%2C-5%2C7%2C-6%2C6%2C+%0D%0Agraph%28200%2C200%2C-5%2C7%2C-6%2C6%29%2C%0D%0Aline%282%2B.1%2C0%2C2-.1%2C0%29%2C+line%282%2C0%2B.1%2C2%2C0-.1%29%2C+line%282%2B.1%2C0%2B.1%2C2-.1%2C0-.1%29%2C+line%282%2B.1%2C0-.1%2C2-.1%2C0%2B.1%29%2C%0D%0A%0D%0Aline%284%2B.1%2C0%2C4-.1%2C0%29%2C+line%284%2C0%2B.1%2C4%2C0-.1%29%2C+line%284%2B.1%2C0%2B.1%2C4-.1%2C0-.1%29%2C+line%284%2B.1%2C0-.1%2C4-.1%2C0%2B.1%29%2C%0D%0A%0D%0A%0D%0Aline%283%2B.1%2C-2%2C3-.1%2C-2%29%2C+line%283%2C-2%2B.1%2C3%2C-2-.1%29%2C+line%283%2B.1%2C-2%2B.1%2C3-.1%2C-2-.1%29%2C+line%283%2B.1%2C-2-.1%2C3-.1%2C-2%2B.1%29++%29

Then we draw the v-shaped graph:

drawing%28200%2C200%2C-5%2C7%2C-6%2C6%2C+%0D%0Agraph%28200%2C200%2C-5%2C7%2C-6%2C6%2Cabs%282x+-+6%29+-+2%29%2C%0D%0Aline%282%2B.1%2C0%2C2-.1%2C0%29%2C+line%282%2C0%2B.1%2C2%2C0-.1%29%2C+line%282%2B.1%2C0%2B.1%2C2-.1%2C0-.1%29%2C+line%282%2B.1%2C0-.1%2C2-.1%2C0%2B.1%29%2C++%0D%0A%0D%0Aline%284%2B.1%2C0%2C4-.1%2C0%29%2C+line%284%2C0%2B.1%2C4%2C0-.1%29%2C+line%284%2B.1%2C0%2B.1%2C4-.1%2C0-.1%29%2C+line%284%2B.1%2C0-.1%2C4-.1%2C0%2B.1%29%2C%0D%0A%0D%0A%0D%0Aline%283%2B.1%2C-2%2C3-.1%2C-2%29%2C+line%283%2C-2%2B.1%2C3%2C-2-.1%29%2C+line%283%2B.1%2C-2%2B.1%2C3-.1%2C-2-.1%29%2C+line%283%2B.1%2C-2-.1%2C3-.1%2C-2%2B.1%29++%29

That's it.

Edwin