SOLUTION: Factor completely: 8g^2j-12g^3hj
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Question 177124This question is from textbook
: Factor completely: 8g^2j-12g^3hj
This question is from textbook
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Factor completely: 8g^2j-12g^3hj
Common factor: 4g^2j
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8g^2j-12g^3hj = 4g^2j[2 - 3gh]
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Cheers,
Stan H.
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