# SOLUTION: Write an equation in slope-intercept form for the line through points (2,4) and (6,-2).

Algebra ->  Algebra  -> Absolute-value -> SOLUTION: Write an equation in slope-intercept form for the line through points (2,4) and (6,-2).      Log On

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 Question 174921This question is from textbook : Write an equation in slope-intercept form for the line through points (2,4) and (6,-2).This question is from textbook Found 3 solutions by Alan3354, jojo14344, nerdybill:Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!Write an equation in slope-intercept form for the line through points (2,4) and (6,-2). ----------- |x y 1| |2 4 1| = 0 |6 -2 1| x*(4+2) - y*(2-6) + 1*(-4-24) = 0 6x + 4y = 28 2y = -3x + 14 y = (-3/2)x + 7 Answer by jojo14344(1512)   (Show Source): You can put this solution on YOUR website! (2,4) and (6,-2). First we get the thru Point Slope form: Then via Slope-Intercept form: Thru points (2,4): -----> Y-intercept Thru points (6,-2): *THEY SHOULD BE EQUAL which is good. So,via Slope intercept form: Answer See graph to verify: Thank you Jojo Answer by nerdybill(6962)   (Show Source): You can put this solution on YOUR website!First, determine the slope between the two points: (2,4) and (6,-2) m = (y2-y1)/(x2-x1) m = (-2-4)/(6-2) m = (-6)/(4) m = -3/2 . Next, use the slope above and one (2,4) of the two points provided and plug it into the "point-slope" form: y-y1 = m(x-x1) y-4 = (-3/2)(x-2) y-4 = (-3/2)x - 2(-3/2) y-4 = (-3/2)x + 3 y = (-3/2)x + 7 (this is what they're looking for)