You can
put this solution on YOUR website!Write the point-slope form of an equation for the line passing through the point at(3,-6)with slope slope-4/3.
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y-y1 = m*(x-x1) where m = slope, (x1,y1) = (3,-6)
y + 6 = -4/3(x-3)
y+6 = (-4/3)x + 4
y = (-4/3)x - 2 (slope-intercept form)
You can
put this solution on YOUR website!The point-slope for of the equation of a line is (y-y1)=m*(x-x1) Where {x1,y1) is the given point and m the slope.
Substituting the actual values for x1 and y1 we have,
(y-(-6))=-4/3*(x-3)
I hope that this helps.