SOLUTION: Find an equation in slope-intercept form for the line that passes through (-3,1)and (-2,-3).

Question 174831This question is from textbook
: Find an equation in slope-intercept form for the line that passes through (-3,1)and (-2,-3). This question is from textbook

Found 2 solutions by jim_thompson5910, nerdybill:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Rewrite as

Distribute

Multiply

Add 1 to both sides.

Combine like terms.

Simplify

So the equation that goes through the points and is

Notice how the graph of goes through the points and . So this visually verifies our answer.
Graph of through the points and

Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Slope of a line between two points is:
m = (y2-y1)/(x2-x1)
.
So, the two given in your problem is:
(-3,1)and (-2,-3)
plugging it in we get:
m = (-3-1)/(-2-(-3))
m = (-4)/(-2+3)
m = (-4)/(1)
m = -4
.
Now, using the "point slope" form of an equation:
y - y1 = m(x-x1)
Using one of the two points provided along with the calculated slope:
y - 1 = -4(x-(-3))
y - 1 = -4(x+3)
y - 1 = -4x - 12
y = -4x - 11 (this is what they're looking for)

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