SOLUTION: three consecutive intergers whose sum is 99
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Question 168119
:
three consecutive intergers whose sum is 99
Answer by
oscargut(686)
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consecutive integers are n,n+1 and n+2
so n+n+1+n+2=99 then 3n+3=99 then 3n=96 then n=32
Solution: 32,33,34
