SOLUTION: solve the problem and describe the steps you used 7 - 4c = 10c

Algebra.Com
Question 16045: solve the problem and describe the steps you used 7 - 4c = 10c
Answer by AnlytcPhil(1806)   (Show Source): You can put this solution on YOUR website!

solve the problem and describe the steps you used
7 - 4c = 10c
`
`
7 - 4c = 10c
`
There are two terms on the left. They are 7 and -4c. There is one
term on the right, 10c.
`
We want to get rid of all terms on the left which DON'T contain c, and
get rid of all terms on the right that DO contain c.
`
The term 7 is on the left and does not contain c. So we get rid of it
on the left by adding the opposite of 7, namely -7, to both sides of
the equation:
`
` ` ` ` ` ` ` ` `7 - 4c = 10c
`
` ` ` ` ` ` `7 - 4c - 7 = 10c - 7
`
That gives ` ` ` ` `-4c = 10c - 7
`
The term 10c on the right contains c. So we get rid of it on the right
by adding the opposite of 10c, namely -10c, to both sides of
the equation:
`
` ` ` ` ` ` ` -4c - 10c = 10c - 7 - 10c
`
That gives ` ` ` ` -14c = -7
`
Now we divide both sides of the equation by the coefficient of c on the left, which is -14:
`
` ` ` ` ` ` ` ` ` `-14c` ` `-7
` ` ` ` ` ` ` ` ` ------ = -----
` ` ` ` ` ` ` ` ` ` -14 ` ` -14
`
Now cancel the -14's on the left, and cancel the negative signs on the right, and get
` ` ` ` ` ` ` ` ` ` ` ` ` ` `7
` ` ` ` ` ` ` ` ` ` ` `c = -----
` ` ` ` ` ` ` ` ` ` ` ` ` ` 14
`
Now reduce 7/14 to 1/2
`
` ` ` ` ` ` ` ` ` ` ` ` ` ` 1
` ` ` ` ` ` ` ` ` ` ` `c = ---
` ` ` ` ` ` ` ` ` ` ` ` ` ` 2
`
Edwin
AnlytcPhil@aol.com

RELATED QUESTIONS

how do you solve... (answered by rfer)
hi my problem is, -7-4c=10c thank you... (answered by askmemath)
7-4c=10c (answered by LilSkittleMd)
7-4c=10c (answered by SnowXclouD)
7-4c=10c (answered by checkley71)
Add 10c-1 and... (answered by jim_thompson5910)
Solve -5e^-4x+2 +3=1/2log(x^2+1) and describe the steps you used. Round your answer to... (answered by ikleyn)
7-4c=10c and also... (answered by stanbon)
describe the steps you would use to solve the equation: 4x+7=15 can you please help (answered by rfer)