SOLUTION: Remember to isolate the absolute value.
|x | = 6
|3x + 2| = 14
- 5| x + 1| = -10
|x - 2| + 10 = 12
|x| = - 5
|2x + 6| - 4 = 20
6 - 3|2x + 6| = 0
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Question 154544: Remember to isolate the absolute value.
|x | = 6
|3x + 2| = 14
- 5| x + 1| = -10
|x - 2| + 10 = 12
|x| = - 5
|2x + 6| - 4 = 20
6 - 3|2x + 6| = 0
10 - |x + 2| = 12
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
To solve these:
1) Get everything not in the absolute sign on the right side of the equal sign.
2) Solve the equation.
3) Multiply everything on the right side of the equal sign by -1.
4) Solve that equation.
.
|2x + 6| - 4 = 20
|2x+6|=24
2x+6=24
2x=18
x=9
.
|2x+6|=24
2x+6=-24
2x=-30
x=-15
.
.
6 - 3|2x + 6| = 0
-3|2x+6|=-6
|2x+6|=2
2x+6=2
2x=-4
x=-2
.
|2x+6|=2
2x+6=-2
2x=-8
x=-4
.
.
10 - |x + 2| = 12
-|x+2|=2
|x+2|=-2
An absolute cannot be negative. There is no answer.
.
Ed
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