SOLUTION: I am so confused about this question, I don't know where to start. This is how it was typed on the word document. . Jack was able to travel 30 miles downstream in 2 hours. In r

Question 143508: I am so confused about this question, I don't know where to start. This is how it was typed on the word document.
. Jack was able to travel 30 miles downstream in 2 hours. In returning upstream, it took 3 hours to make the trip. How fast can his boat travel in still water? What was the rate of the river current?

2(r+c)=30--->2r+2c=30-->6r+6c=90
3(r-c)=30---->3r-3c=30--> 6r+6c=60

Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Minor error is causing you grief
2(r+c)=30--->2r+2c=30-->6r+6c=90
3(r-c)=30---->3r-3c=30--> 6r+6c=60 <-- you changed - to + here
3(r-c)=30---->3r-3c=30--> 6r-6c=60 should be this
Now just use elimination to solve. See here for a video on solving systems of equations. http://collabvsl.wetpaint.com/page/Solving+Systems+of+Equations
6r + 6c = 90
6r - 6c = 60
------------
12r = 150
r = 12.5
r+c = 15
12.5 + c = 15
c = 2.5
Does that check out?

RELATED QUESTIONS
Hello! I am very confused on a question for homework, and don't know where to start. It... (answered by ikleyn)

I'm not sure if this question goes here, but it's about finding the sub-problems and... (answered by jsmallt9)

Hello, I am confused on this question | q - 8 | = 14 , I've tried it but I've gotten... (answered by josgarithmetic,MathTherapy,ikleyn)

Hi, I had just learned about probability, premutaions and combinations, but I am a bit... (answered by rothauserc)

Hi. I am writing is to inform you that I really need help in solving distance word... (answered by 24HoursTutor.com)

These problems I have been working on all weekend, and I do not understand. My grade and... (answered by stanbon)

Hello! I am unsure that this is the right topic to submit this question to, but I am... (answered by ankor@dixie-net.com)

How do i solve this proof? I will attach a picture to this so you can open it and see... (answered by Edwin McCravy)