|2x| < x+5
Case 1: x > 0 and |2x| < x+5
Then |2x| = 2x and
x > 0 and 2x < x + 5
x > 0 and x < 5
[0, 5)
Case 2: x < 0 and |2x| < x+5
Then |2x| = -2x and
x < 0 and -2x < x + 5
x < 0 and -3x < 5
x < 0 and x > -5/3
(-5/3, 0)
So solution is
Case 2 U Case 1
(-5/3, 0) U [0, 5)
or
(-5/3, 5)
Edwin