If 3 < x < 5, then a) x-3 > 0; therefore, |x-3| = x-3; b) x+2 > 0; therefore, |x+2| = x+2; c) x-5 < 0; therefore, |x-5| = -(x-5). THEREFORE, y = |x-3| + |x+2| - |x-5| = (x-3) + (x+2) + (x-5) = 3x - 6. ANSWER