SOLUTION: If two people have a dinner together and it costs $60.26 and one person paid $5 more than one-half of the others person bill how much money did they both spend separably?

Algebra ->  Absolute-value -> SOLUTION: If two people have a dinner together and it costs $60.26 and one person paid $5 more than one-half of the others person bill how much money did they both spend separably?       Log On


   

Question 1139672: If two people have a dinner together and it costs $60.26 and one person paid $5 more than one-half of the others person bill how much money did they both spend separably?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = one person's spending
+%281%2F2%29%2Ax+%2B+5+ = the other person's spending
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+x+%2B+%281%2F2%29%2Ax+%2B+5+=+60.26+
Multiply both sides by +2+
+2x+%2B+x+%2B+10+=+120.52+
+3x+=+110.52+
+x+=+36.84+
and
+60.26+-+36.84+=+23.42+
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They each spent:
$23.42
$36.83
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check:
+%281%2F2%29%2Ax+%2B+5+=+23.42+
+x+%2B+10+=+46.84+
+36.83+%2B+10+=+46.84+
I'm off by 1 cent
Can you see why?
I'm out of time