3|x+5| <= 6 Divide both side by 3. You will get an equivalent inequality |x + 5| <= 2, or, which is the same, |x - (-5)| <= 2. The solution is the set of those x's that are remoted not far than 2 units from -5; in other words, -5-2 <= x <= -5 + 2, or -7 <= x <= -3. Answer. The solution set is -7 <= x <= -3, or, in the interval notation, the segment [-7,-3].