SOLUTION: a^2+1 = 9a (a not equal to 0 ) then find a^2 + 1/a^2 is

Question 1087961: a^2+1 = 9a (a not equal to 0 ) then find a^2 + 1/a^2 is
Answer by ikleyn(52817) (Show Source): You can put this solution on YOUR website!
.

If  a^2+1 = 9a   then divide both sides by "a", and you will get

     = 9.   (1)


    Now square both sides of (1). You will get

     +  = 81,    and then

     +  = 81 - 2 = 79.

Answer. 79.

Solved.

RELATED QUESTIONS
If a+1/3a=2 then find the value of... (answered by greenestamps,math_tutor2020)

If sin 6A = cos 9A, then the measure of angle A is equal to 1) 6 2) 54 3) 36 4)... (answered by Theo)

If a+1/a=2 find... (answered by ikleyn)

If a+1/3a=2 find the value of... (answered by ikleyn)

I need to find the quotient using long division. 9a^3-3a^2-3a+4 divided by 3a+2 I... (answered by richwmiller)

Simplify the variable expression below. (1/9a) - (2/3a) a. -5/18a b. -5/9a c.... (answered by robertb)

If a^2 + a + 1 = 0 , then one value of a^3 + 1 is equal to (1)0 (2)1 (3)2 (4)4... (answered by josgarithmetic)

Find the general equation of a line passing through (0,k) and (k,k^2) given that k is not (answered by Boreal)

(a^2-36)/(a^2+9a+18) (answered by mananth)