SOLUTION: Solve for x where a, p > 0: p|ax + b|-q ≤ 0

Algebra.Com
Question 1086171: Solve for x where a, p > 0: p|ax + b|-q ≤ 0
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Solve for x where a, p > 0: p|ax + b|-q ≤ 0




The left side is non-negative so q is non-negative.

Case 1:  q = 0 

, and since p > 0, 

ax + b = 0 
    ax = -b
     x = -b/a

So if q=0, then x = -b/a

Case 2: q > 0

, 

,







Edwin
RELATED QUESTIONS

y ≤ ax+b when (a<0) Solve for... (answered by lwsshak3)
Please help me to solve this problem. The demand equation for a manufacturer's product is (answered by richard1234)
The function below describes the market penetration of a product, where p, q, and C are... (answered by Fombitz)
consider the integral expression in x! {{{P=x^3+x^2+ax+1}}} where a is rational number (answered by KMST)
Solve this equation for 0≤x≤2p, giving your answer (answered by Edwin McCravy)
All the roots of x^2 + px + q = 0 are real, where p and q are real numbers. Prove that... (answered by ikleyn)
Find the following probabilities: a)P (0 ≤ Z ≤ .5) b)P (Z ≤ .5)... (answered by ewatrrr)
consider the inequality 6x + y < p. What must be true about the value of p in order for... (answered by KMST)
p=-1/10x+150 0 ≤ x ≤ 1500 Revenue is x*p. (a) Express the revenue R... (answered by solver91311)