SOLUTION: Assume that women's heights are normally distributed with a mean given �= 62.1 in, and a standard deviation given by �=2.9 in If 40 women are randomly selected find the probabi

Question 1009613: Assume that women's heights are normally distributed with a mean given �= 62.1 in, and a standard deviation given by �=2.9 in
If 40 women are randomly selected find the probability that they have a mean height less than 63 in
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
z= (x-mean)/SD/sqrt(n)
=(63-62.1)/(2.9/sqrt(40))
=0.9/0.4585
=1.963
This is the probability that the z score is less than 1.963, which is 0.9752.
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