SOLUTION: The dimensions of a rectangle are such that length is 9 inches more than width. If the length is doubled and the width decreased by 4 in. The are would be increased by 138 in ^. Wh

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Question 980216: The dimensions of a rectangle are such that length is 9 inches more than width. If the length is doubled and the width decreased by 4 in. The are would be increased by 138 in ^. What are the length and width of the rectangle
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
x=9+y for length with width y.
Area is .

New rectangle,
----OBVIOUS MISTAKE MADE HERE.
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Simplify this new rectangle equation.




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What to do next, is substitute for A using the original area equation.




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The meaningful value for *y is .
*.
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*Those are wrong, because of the noted OBVIOUS MISTAKE.
New rectangle width should be y-4, not y+4.


DONE CORRECTLY, THIS IS HOW THE STEPS GO:
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NEW:






-

-
Returning to


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The dimensions of a rectangle are such that length is 9 inches more than width. If the length is doubled and the width decreased by 4 in. The are would be increased by 138 in ^. What are the length and width of the rectangle
Width of original rectangle:  in

Length of original rectangle: 14 + 9, or  im 

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