SOLUTION: I have a Geometry problem here that I need help on. The dimensions of something are 8.0 ft x 7.0 ft x.75ft , and the area of it is 42 ft^3. I need to know how many g/cm^3's ar

Question 658040: I have a Geometry problem here that I need help on.
The dimensions of something are 8.0 ft x 7.0 ft x.75ft , and the area of it is 42 ft^3. I need to know how many g/cm^3's are required to fill this. Can you help me?
Answer by colliefan(242) (Show Source): You can put this solution on YOUR website!
I think it says that the volume is 42 ft^3. Area would be in square feet.
The way they got the volume was:
V=length*width*height
V=8.0 ft * 7.0 ft * 0.75 ft
V =42 ft^3

To calculate the volume in cm, convert the l, w, and h to centimeters before multiplying. Then, the unit of the volume will be cm^3.
To convert feet to cm, do it in steps. Go to inches first and then to centimeters. I do this with the "unit factor" method. If you multiply a number by 1, you do not change the number. If you put things that are equal in a ratio, you are multiplying by 1 and you only change the units. This is a very useful technique in physics and chemistry.
Eg:
8 ft * 12 inches/1 foot *2.54 cm/inch = 243.84 cm
7 ft * 12 inches/1 foot *2.54 cm/inch = 213.36 cm
0.75 ft * 12 inches/1 foot *2.54 cm/inch = 22.86 cm
Multiply the l, w, and h in centimeters to get the volume in cm^3.
v= 1189307.56 cm^3

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